What are the solutions to the equation 3x^2+9x+4=0 ?

The solutions to the equation 3x^2+9x+4=0 are x=(-9+sqrt(33))/6 ,x=(-9-sqrt(33))/6

Find the zeros of 3x^2+9x+4=0

The zeros of 3x^2+9x+4=0 are x=(-9+sqrt(33))/6 ,x=(-9-sqrt(33))/6

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3 x^{2} + 9 x + 4 = 0

x = \frac{- 9 + 33}{6}, x = \frac{- 9 - 33}{6}

Solution steps

3 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

9^{2} - 4 \cdot 3 \cdot 4 = 33

x_{1, 2} = \frac{- 9 \pm 33}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 33}{2 \cdot 3}, x_{2} = \frac{- 9 - 33}{2 \cdot 3}

x = \frac{- 9 + 33}{2 \cdot 3} : \frac{- 9 + 33}{6}

x = \frac{- 9 - 33}{2 \cdot 3} : \frac{- 9 - 33}{6}

The solutions to the quadratic equation are:

x = \frac{- 9 + 33}{6}, x = \frac{- 9 - 33}{6}

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What are the solutions to the equation 3x^2+9x+4=0 ?
The solutions to the equation 3x^2+9x+4=0 are x=(-9+sqrt(33))/6 ,x=(-9-sqrt(33))/6
Find the zeros of 3x^2+9x+4=0
The zeros of 3x^2+9x+4=0 are x=(-9+sqrt(33))/6 ,x=(-9-sqrt(33))/6