What is the answer to solvefor x,0=2x-(3-x)^{-1} ?

The answer to solvefor x,0=2x-(3-x)^{-1} is x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2

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solvefor x,0=2x-(3-x)^{-1}

solve for

x, 0 = 2 x - (3 - x)^{- 1}

x = \frac{3 - 7}{2}, x = \frac{3 + 7}{2}

Solution steps

0 = 2 x - (3 - x)^{- 1}

Refine

0 = 2 x - \frac{1}{3 - x}

Multiply both sides by

3 - x

0 = 2 x (3 - x) - 1

Solve

0 = 2 x (3 - x) - 1 : x = \frac{3 - 7}{2}, x = \frac{3 + 7}{2}

x = \frac{3 - 7}{2}, x = \frac{3 + 7}{2}

Verify Solutions

Find undefined (singularity) points:

x = 3

Combine undefined points with solutions:

x = \frac{3 - 7}{2}, x = \frac{3 + 7}{2}

\frac{8}{a x} - 5 = 3

2 - \frac{9 x + 9}{4 x} = - \frac{3}{2}

\frac{4}{x + 3} = \frac{3}{10}

\frac{112 + k}{112 + 2 k} = 0

\frac{x - 5}{- x} = 3

What is the answer to solvefor x,0=2x-(3-x)^{-1} ?
The answer to solvefor x,0=2x-(3-x)^{-1} is x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2