What is the answer to solvefor a,u=-(2a-3)/(ka) ?

The answer to solvefor a,u=-(2a-3)/(ka) is a= 3/(ku+2);\quad k\ne 0,k\ne-2/u

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solvefor a,u=-(2a-3)/(ka)

solve for

a, u = - \frac{2 a - 3}{ka}

a = \frac{3}{k u + 2}; k \neq = 0, k \neq = - \frac{2}{u}

Solution steps

u = - \frac{2 a - 3}{ka}

Multiply both sides by

a

u a = - \frac{2 a - 3}{k}

Multiply both sides by

k

u ak = - (2 a - 3); k \neq = 0

Expand

- (2 a - 3) : - 2 a + 3

u ak = - 2 a + 3; k \neq = 0

Move

2 a

to the left side

u ak + 2 a = 3; k \neq = 0

Factor

u ak + 2 a : a (k u + 2)

a (k u + 2) = 3; k \neq = 0

Divide both sides by

k u + 2; k \neq = 0, k \neq = - \frac{2}{u}

a = \frac{3}{k u + 2}; k \neq = 0, k \neq = - \frac{2}{u}

\frac{10}{m} = \frac{5}{11}

- 0.9 = \frac{550500 - 562750}{x}

\frac{3}{2500} = \frac{1}{x}

a, z = - \frac{3}{2 a p n}

a, R = \frac{a}{1 - a}

What is the answer to solvefor a,u=-(2a-3)/(ka) ?
The answer to solvefor a,u=-(2a-3)/(ka) is a= 3/(ku+2);\quad k\ne 0,k\ne-2/u