What is the answer to 0=(x+1)/(x^2-81) ?

The answer to 0=(x+1)/(x^2-81) is x=-1

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0=(x+1)/(x^2-81)

0 = \frac{x + 1}{x ^{2} - 81}

x = - 1

Solution steps

0 = \frac{x + 1}{x ^{2} - 81}

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

0 = x + 1

Switch sides

x + 1 = 0

Move

1

to the right side

x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 9, x = - 9

Combine undefined points with solutions:

x = - 1

x, \frac{1 + y}{2 + x} = 3 y

1 - \frac{1}{( x - 5 ) ^{2}} = 0

\frac{8 m ^{2} + 5 m - 3}{5 m + 5} = 1

\frac{7}{5} = \frac{42}{b}

\frac{x}{x + 3} = \frac{3}{2}