What is the answer to x^{-2}+x^{-1}=6 ?

The answer to x^{-2}+x^{-1}=6 is x= 1/2 ,x=-1/3

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x^{-2}+x^{-1}=6

x^{- 2} + x^{- 1} = 6

x = \frac{1}{2}, x = - \frac{1}{3}

Decimal Notation

x = 0.5, x = - 0.33333 \dots

Solution steps

x^{- 2} + x^{- 1} = 6

Refine

\frac{1}{x ^{2}} + \frac{1}{x} = 6

Multiply by LCM

1 + x = 6 x^{2}

Solve

1 + x = 6 x^{2} : x = \frac{1}{2}, x = - \frac{1}{3}

x = \frac{1}{2}, x = - \frac{1}{3}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{2}, x = - \frac{1}{3}

- \frac{3}{( x - 5 ) ^{2}} = 0

\frac{4 x}{x - 2} + \frac{6}{x + 2} = 3

\frac{3}{2 x + 1} = - \frac{1}{4 - 3 x}

6 + \frac{7}{y - 1} = \frac{2}{y + 2}

\frac{4}{y - 2} = - 9 - \frac{2}{y - 1}

What is the answer to x^{-2}+x^{-1}=6 ?
The answer to x^{-2}+x^{-1}=6 is x= 1/2 ,x=-1/3
Solve for x: x^{-2}+x^{-1}=6
The solution is x= 1/2 ,x=-1/3