What are the solutions to the equation 3x^2-18x+15=0 ?

The solutions to the equation 3x^2-18x+15=0 are x=5,x=1

Find the zeros of 3x^2-18x+15=0

The zeros of 3x^2-18x+15=0 are x=5,x=1

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3 x^{2} - 18 x + 15 = 0

x = 5, x = 1

Solution steps

3 x^{2} - 18 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 15}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 15 = 12

x_{1, 2} = \frac{- ( - 18 ) \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 12}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 12}{2 \cdot 3}

x = \frac{- ( - 18 ) + 12}{2 \cdot 3} : 5

x = \frac{- ( - 18 ) - 12}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

(x + 7)^{2} = 100

x - x - 1 + x + 2 \geq 0

12 5^{\frac{1}{4}} \cdot 5^{\frac{1}{4}}

x^{2} - 196 y^{2}

7 (5 x - 7)^{2} + 9 (5 x - 7) (x + 9)

What are the solutions to the equation 3x^2-18x+15=0 ?
The solutions to the equation 3x^2-18x+15=0 are x=5,x=1
Find the zeros of 3x^2-18x+15=0
The zeros of 3x^2-18x+15=0 are x=5,x=1