What is the answer to ((x^2-2x))/((x-1)^2)=0 ?

The answer to ((x^2-2x))/((x-1)^2)=0 is x=2,x=0

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((x^2-2x))/((x-1)^2)=0

\frac{( x ^{2} - 2 x )}{( x - 1 ) ^{2}} = 0

x = 2, x = 0

Solution steps

\frac{( x ^{2} - 2 x )}{( x - 1 ) ^{2}} = 0

Simplify

\frac{( x ^{2} - 2 x )}{( x - 1 ) ^{2}} : \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 2 x = 0

Solve

x^{2} - 2 x = 0 : x = 2, x = 0

x = 2, x = 0

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = 2, x = 0

\frac{3 x + 1}{x + 4} = 2

5 = \frac{40}{x}

295 = 4 8^{2} \frac{( 8 + x )}{11 x + 24}

\frac{42}{t} = 7

\frac{x + 1}{x - 1} = \frac{10}{5}

What is the answer to ((x^2-2x))/((x-1)^2)=0 ?
The answer to ((x^2-2x))/((x-1)^2)=0 is x=2,x=0
Solve for x: ((x^2-2x))/((x-1)^2)=0
The solution is x=2,x=0