What is the answer to 2y^{-2}+7y^{-1}-4=0 ?

The answer to 2y^{-2}+7y^{-1}-4=0 is y=-1/4 ,y=2

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2y^{-2}+7y^{-1}-4=0

2 y^{- 2} + 7 y^{- 1} - 4 = 0

y = - \frac{1}{4}, y = 2

Decimal Notation

y = - 0.25, y = 2

Solution steps

2 y^{- 2} + 7 y^{- 1} - 4 = 0

Refine

\frac{2}{y ^{2}} + \frac{7}{y} - 4 = 0

Multiply by LCM

2 + 7 y - 4 y^{2} = 0

Solve

2 + 7 y - 4 y^{2} = 0 : y = - \frac{1}{4}, y = 2

y = - \frac{1}{4}, y = 2

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y = - \frac{1}{4}, y = 2

(1) = \frac{1}{s ^{2}}

a, p = \frac{w}{ab}

\frac{m}{( L + m )} = \frac{n}{p}

0.2 = \frac{x}{1 - x}

\frac{2 x}{5 x + 4} = \frac{10}{27}

What is the answer to 2y^{-2}+7y^{-1}-4=0 ?
The answer to 2y^{-2}+7y^{-1}-4=0 is y=-1/4 ,y=2
Solve for y: 2y^{-2}+7y^{-1}-4=0
The solution is y=-1/4 ,y=2