What is the answer to -k^2+3k-2/k =1 ?

The answer to -k^2+3k-2/k =1 is k=2,k=(1+sqrt(5))/2 ,k=(1-sqrt(5))/2

Solve for k: -k^2+3k-2/k =1

The solution is k=2,k=(1+sqrt(5))/2 ,k=(1-sqrt(5))/2

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- k^{2} + 3 k - \frac{2}{k} = 1

k = 2, k = \frac{1 + 5}{2}, k = \frac{1 - 5}{2}

Decimal Notation

k = 2, k = 1.61803 \dots, k = - 0.61803 \dots

Solution steps

- k^{2} + 3 k - \frac{2}{k} = 1

Multiply both sides by

k

- k^{3} + 3 k^{2} - 2 = k

Solve

- k^{3} + 3 k^{2} - 2 = k : k = 2, k = \frac{1 + 5}{2}, k = \frac{1 - 5}{2}

k = 2, k = \frac{1 + 5}{2}, k = \frac{1 - 5}{2}

Verify Solutions

Find undefined (singularity) points:

k = 0

Combine undefined points with solutions:

k = 2, k = \frac{1 + 5}{2}, k = \frac{1 - 5}{2}

\frac{x - 3}{5 x} + 1 = \frac{x + 2}{x}

9 - \frac{4}{x ^{2}} = 0

\frac{3}{342} = \frac{4}{x}

3 - \frac{x}{x - 4} = \frac{4}{4 - x}

\frac{5 - 2 x}{2 x} + 1 = \frac{5}{2 x}

What is the answer to -k^2+3k-2/k =1 ?
The answer to -k^2+3k-2/k =1 is k=2,k=(1+sqrt(5))/2 ,k=(1-sqrt(5))/2
Solve for k: -k^2+3k-2/k =1
The solution is k=2,k=(1+sqrt(5))/2 ,k=(1-sqrt(5))/2