What are the solutions to the equation 2c^2+4c+14=c^2+9 ?

The solutions to the equation 2c^2+4c+14=c^2+9 are c=-2+i,c=-2-i

Find the zeros of 2c^2+4c+14=c^2+9

The zeros of 2c^2+4c+14=c^2+9 are c=-2+i,c=-2-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 c^{2} + 4 c + 14 = c^{2} + 9

c = - 2 + i, c = - 2 - i

Solution steps

2 c^{2} + 4 c + 14 = c^{2} + 9

Move

9

to the left side

2 c^{2} + 4 c + 5 = c^{2}

Move

c^{2}

to the left side

c^{2} + 4 c + 5 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

c_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, c_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

c = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

c = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

c = - 2 + i, c = - 2 - i

- 2 x^{2} + 6 x + 3 = 0

w^{2} + 11 w + 30 = 0

\frac{5}{2} - 4

(\frac{5}{8})^{1}

4 z^{2} + 5 z - 6

What are the solutions to the equation 2c^2+4c+14=c^2+9 ?
The solutions to the equation 2c^2+4c+14=c^2+9 are c=-2+i,c=-2-i
Find the zeros of 2c^2+4c+14=c^2+9
The zeros of 2c^2+4c+14=c^2+9 are c=-2+i,c=-2-i