What is the answer to (x^2+x)/(x^2+4x-12)=0 ?

The answer to (x^2+x)/(x^2+4x-12)=0 is x=0,x=-1

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(x^2+x)/(x^2+4x-12)=0

\frac{x ^{2} + x}{x ^{2} + 4 x - 12} = 0

x = 0, x = - 1

Solution steps

\frac{x ^{2} + x}{x ^{2} + 4 x - 12} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + x = 0

Solve

x^{2} + x = 0 : x = 0, x = - 1

x = 0, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 2, x = - 6

Combine undefined points with solutions:

x = 0, x = - 1

x \frac{10}{x + 18} = \frac{x + 1}{6}

\frac{1}{3 x + 3} = 23

x^{- 1} = \frac{1}{2}

x^{- 1} = \frac{1}{6}

x, F = \frac{K}{1 + x}

What is the answer to (x^2+x)/(x^2+4x-12)=0 ?
The answer to (x^2+x)/(x^2+4x-12)=0 is x=0,x=-1
Solve for x: (x^2+x)/(x^2+4x-12)=0
The solution is x=0,x=-1