What is the answer to x^{-n-1}= 1/(x^{n-1)} ?

The answer to x^{-n-1}= 1/(x^{n-1)} is x=1,x=-1;\quad x^{n-1}\ne 0

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x^{-n-1}= 1/(x^{n-1)}

x^{- n - 1} = \frac{1}{x ^{n - 1}}

x = 1, x = - 1; x^{n - 1} \neq = 0

Solution steps

x^{- n - 1} = \frac{1}{x ^{n - 1}}

Multiply both sides by

x^{n - 1}

\frac{1}{x ^{2}} = 1; x^{n - 1} \neq = 0

Multiply both sides by

x^{2}

1 = x^{2}; x^{n - 1} \neq = 0

Solve

1 = x^{2} : x = 1, x = - 1

x = 1, x = - 1; x^{n - 1} \neq = 0

\frac{a}{x ^{2}} + b x^{2} = - 21

\frac{1}{x + 2} = x^{3} + 7 x + 7

\frac{3}{1} = \frac{22}{x}

\frac{2}{x + 1} = \frac{5}{x - 3}

\frac{2 x}{x ^{2} + 4} = 0

What is the answer to x^{-n-1}= 1/(x^{n-1)} ?
The answer to x^{-n-1}= 1/(x^{n-1)} is x=1,x=-1;\quad x^{n-1}\ne 0