What are the solutions to the equation -x^2-4x+2=0 ?

The solutions to the equation -x^2-4x+2=0 are x=-2-sqrt(6),x=sqrt(6)-2

Find the zeros of -x^2-4x+2=0

The zeros of -x^2-4x+2=0 are x=-2-sqrt(6),x=sqrt(6)-2

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- x^{2} - 4 x + 2 = 0

x = - 2 - 6, x = 6 - 2

Solution steps

- x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) \cdot 2 = 26

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 2 6}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 2 6}{2 ( - 1 )} : - 2 - 6

x = \frac{- ( - 4 ) - 2 6}{2 ( - 1 )} : 6 - 2

The solutions to the quadratic equation are:

x = - 2 - 6, x = 6 - 2

\frac{5}{7} - \frac{3}{7}

28 - 7 x \leq - 4 (- 7 x - 7)

(x + y)^{2} + 3 (x + y)

12 x^{2} - 11 x + 2 = 0

x^{2} + 3 x - 24 = 3 x + 1

What are the solutions to the equation -x^2-4x+2=0 ?
The solutions to the equation -x^2-4x+2=0 are x=-2-sqrt(6),x=sqrt(6)-2
Find the zeros of -x^2-4x+2=0
The zeros of -x^2-4x+2=0 are x=-2-sqrt(6),x=sqrt(6)-2