What is the answer to (x^2-4)/(x^2-4x+4)=-1 ?

The answer to (x^2-4)/(x^2-4x+4)=-1 is x=0

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(x^2-4)/(x^2-4x+4)=-1

\frac{x ^{2} - 4}{x ^{2} - 4 x + 4} = - 1

x = 0

Solution steps

\frac{x ^{2} - 4}{x ^{2} - 4 x + 4} = - 1

Simplify

\frac{x ^{2} - 4}{x ^{2} - 4 x + 4} : \frac{x + 2}{x - 2}

\frac{x + 2}{x - 2} = - 1

Multiply both sides by

x - 2

x + 2 = - (x - 2)

Expand

- (x - 2) : - x + 2

x + 2 = - x + 2

Move

2

to the right side

x = - x

Move

x

to the left side

2 x = 0

Divide both sides by

2

x = 0

Verify Solutions

Find undefined (singularity) points:

x = 2

Combine undefined points with solutions:

x = 0

- x = x^{- 1}

\frac{1.204}{x} = 0.565

\frac{- 2}{3 b} = 75

\frac{2500}{( 10 + y ) ^{2}} - 1 = 0

\frac{2 x}{x + 1} = \frac{3 x}{9}

What is the answer to (x^2-4)/(x^2-4x+4)=-1 ?
The answer to (x^2-4)/(x^2-4x+4)=-1 is x=0
Solve for x: (x^2-4)/(x^2-4x+4)=-1
The solution is x=0