What is the answer to (x^3+x+2)/(x^2+1)=2 ?

The answer to (x^3+x+2)/(x^2+1)=2 is x=0,x=1

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(x^3+x+2)/(x^2+1)=2

\frac{x ^{3} + x + 2}{x ^{2} + 1} = 2

x = 0, x = 1

Solution steps

\frac{x ^{3} + x + 2}{x ^{2} + 1} = 2

Multiply both sides by

x^{2} + 1

x^{3} + x + 2 = 2 (x^{2} + 1)

Solve

x^{3} + x + 2 = 2 (x^{2} + 1) : x = 0, x = 1

x = 0, x = 1

\frac{7}{3} = \frac{42}{y}

- 4 = \frac{x}{1200 - x}

\frac{5 x - 45}{x - 9} = 5

b, \frac{2 π}{b} = 4

\frac{200 x - 5000}{200 x} = 0.3

What is the answer to (x^3+x+2)/(x^2+1)=2 ?
The answer to (x^3+x+2)/(x^2+1)=2 is x=0,x=1
Solve for x: (x^3+x+2)/(x^2+1)=2
The solution is x=0,x=1