What is the answer to k/4 =(k^2-1)/k ?

The answer to k/4 =(k^2-1)/k is k= 2/(sqrt(3)),k=-2/(sqrt(3))

Solve for k: k/4 =(k^2-1)/k

The solution is k= 2/(sqrt(3)),k=-2/(sqrt(3))

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\frac{k}{4} = \frac{k ^{2} - 1}{k}

k = \frac{2}{3}, k = - \frac{2}{3}

Decimal Notation

k = 1.15470 \dots, k = - 1.15470 \dots

Solution steps

\frac{k}{4} = \frac{k ^{2} - 1}{k}

Cross multiply

k^{2} = 4 (k^{2} - 1)

Solve

k^{2} = 4 (k^{2} - 1) : k = \frac{2}{3}, k = - \frac{2}{3}

k = \frac{2}{3}, k = - \frac{2}{3}

Verify Solutions

Find undefined (singularity) points:

k = 0

Combine undefined points with solutions:

k = \frac{2}{3}, k = - \frac{2}{3}

3 - \frac{2}{9 b} = \frac{1}{3 b} - 7

x = 4 - \frac{1}{x}

x \frac{4}{x + 3} = \frac{6}{x + 3} + 2

F = \frac{G m ^{1} m ^{2}}{d ^{2}}

\frac{20}{5} = \frac{16}{n}

What is the answer to k/4 =(k^2-1)/k ?
The answer to k/4 =(k^2-1)/k is k= 2/(sqrt(3)),k=-2/(sqrt(3))
Solve for k: k/4 =(k^2-1)/k
The solution is k= 2/(sqrt(3)),k=-2/(sqrt(3))