What are the solutions to the equation 5x^2+4=2x+4 ?

The solutions to the equation 5x^2+4=2x+4 are x= 2/5 ,x=0

Find the zeros of 5x^2+4=2x+4

The zeros of 5x^2+4=2x+4 are x= 2/5 ,x=0

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5 x^{2} + 4 = 2 x + 4

x = \frac{2}{5}, x = 0

Solution steps

5 x^{2} + 4 = 2 x + 4

Move

4

to the left side

5 x^{2} = 2 x

Move

2 x

to the left side

5 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 5}

x = \frac{- ( - 2 ) + 2}{2 \cdot 5} : \frac{2}{5}

x = \frac{- ( - 2 ) - 2}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = 0

540

- 9 < 5 - 7 y \leq 12

(\frac{1 + i}{1 - i})^{\frac{1}{6}}

- \frac{2}{2}

What are the solutions to the equation 5x^2+4=2x+4 ?
The solutions to the equation 5x^2+4=2x+4 are x= 2/5 ,x=0
Find the zeros of 5x^2+4=2x+4
The zeros of 5x^2+4=2x+4 are x= 2/5 ,x=0