What is the answer to (x^2-2x)/(x^2-2x+1)=0 ?

The answer to (x^2-2x)/(x^2-2x+1)=0 is x=2,x=0

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(x^2-2x)/(x^2-2x+1)=0

\frac{x ^{2} - 2 x}{x ^{2} - 2 x + 1} = 0

x = 2, x = 0

Solution steps

\frac{x ^{2} - 2 x}{x ^{2} - 2 x + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 2 x = 0

Solve

x^{2} - 2 x = 0 : x = 2, x = 0

x = 2, x = 0

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = 2, x = 0

\frac{x + 2}{x + 1} = 5

0 = 4 - \frac{1}{x ^{2}}

\frac{x + 2}{x + 1} = 0

32 (\frac{1 - 1}{x}) = 25

\frac{4}{x - 4} = \frac{10}{x - 5}

What is the answer to (x^2-2x)/(x^2-2x+1)=0 ?
The answer to (x^2-2x)/(x^2-2x+1)=0 is x=2,x=0
Solve for x: (x^2-2x)/(x^2-2x+1)=0
The solution is x=2,x=0