What is the answer to (x^2-16)/(x-4)+x=x^2-4 ?

The answer to (x^2-16)/(x-4)+x=x^2-4 is x=-2

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(x^2-16)/(x-4)+x=x^2-4

\frac{x ^{2} - 16}{x - 4} + x = x^{2} - 4

x = - 2

Solution steps

\frac{x ^{2} - 16}{x - 4} + x = x^{2} - 4

Simplify

\frac{x ^{2} - 16}{x - 4} : x + 4

x + 4 + x = x^{2} - 4

Solve

x + 4 + x = x^{2} - 4 : x = 4, x = - 2

x = 4, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 4

Since the equation is undefined for:

4

x = - 2

\frac{3}{2 ( 4 x - 8 )} = 12

\frac{7}{x} = 2

\frac{32}{4 + 3 - ( 12 - x )} = 7 - (- 2 - 3)

0 = \frac{3 x ^{2}}{x ^{2} - 4}

\frac{40}{3 x} = 20

What is the answer to (x^2-16)/(x-4)+x=x^2-4 ?
The answer to (x^2-16)/(x-4)+x=x^2-4 is x=-2
Solve for x: (x^2-16)/(x-4)+x=x^2-4
The solution is x=-2