What are the solutions to the equation 4c^2+3c-2=0 ?

The solutions to the equation 4c^2+3c-2=0 are c=(-3+sqrt(41))/8 ,c=(-3-sqrt(41))/8

Find the zeros of 4c^2+3c-2=0

The zeros of 4c^2+3c-2=0 are c=(-3+sqrt(41))/8 ,c=(-3-sqrt(41))/8

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4 c^{2} + 3 c - 2 = 0

c = \frac{- 3 + 41}{8}, c = \frac{- 3 - 41}{8}

Decimal Notation

c = 0.42539 \dots, c = - 1.17539 \dots

Solution steps

4 c^{2} + 3 c - 2 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 2) = 41

c_{1, 2} = \frac{- 3 \pm 41}{2 \cdot 4}

Separate the solutions

c_{1} = \frac{- 3 + 41}{2 \cdot 4}, c_{2} = \frac{- 3 - 41}{2 \cdot 4}

c = \frac{- 3 + 41}{2 \cdot 4} : \frac{- 3 + 41}{8}

c = \frac{- 3 - 41}{2 \cdot 4} : \frac{- 3 - 41}{8}

The solutions to the quadratic equation are:

c = \frac{- 3 + 41}{8}, c = \frac{- 3 - 41}{8}

\frac{5 ^{9}}{5 ^{2}} = 5

m^{2} + 7 = 6

2 v^{2} + 20 v + 60

- 4 - 6

0.25 \cdot 0.25

What are the solutions to the equation 4c^2+3c-2=0 ?
The solutions to the equation 4c^2+3c-2=0 are c=(-3+sqrt(41))/8 ,c=(-3-sqrt(41))/8
Find the zeros of 4c^2+3c-2=0
The zeros of 4c^2+3c-2=0 are c=(-3+sqrt(41))/8 ,c=(-3-sqrt(41))/8