What is the answer to 1/(2x-3)= 3/(3x-2) ?

The answer to 1/(2x-3)= 3/(3x-2) is x= 7/3

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1/(2x-3)= 3/(3x-2)

\frac{1}{2 x - 3} = \frac{3}{3 x - 2}

x = \frac{7}{3}

Decimal Notation

x = 2.33333 \dots

Solution steps

\frac{1}{2 x - 3} = \frac{3}{3 x - 2}

Cross multiply

3 x - 2 = 6 x - 9

Move

2

to the right side

3 x = 6 x - 7

Move

6 x

to the left side

- 3 x = - 7

Divide both sides by

- 3

x = \frac{7}{3}

Verify Solutions

Find undefined (singularity) points:

x = \frac{3}{2}, x = \frac{2}{3}

Combine undefined points with solutions:

x = \frac{7}{3}

\frac{3 x + 3}{3 x - 3} = 0

\frac{3}{q + 9} = \frac{4}{2 q + 6}

- \frac{16}{a} = 3 a - 15

\frac{- 4}{5} = \frac{3}{z - 5}

\frac{2}{3 x} - 5 = x

What is the answer to 1/(2x-3)= 3/(3x-2) ?
The answer to 1/(2x-3)= 3/(3x-2) is x= 7/3
Solve for x: 1/(2x-3)= 3/(3x-2)
The solution is x= 7/3