What is the answer to 1/(3(x+1))=(x+1)/2 ?

The answer to 1/(3(x+1))=(x+1)/2 is x=sqrt(2/3)-1,x=-sqrt(2/3)-1

Solve for x: 1/(3(x+1))=(x+1)/2

The solution is x=sqrt(2/3)-1,x=-sqrt(2/3)-1

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\frac{1}{3 ( x + 1 )} = \frac{x + 1}{2}

x = \frac{2}{3} - 1, x = - \frac{2}{3} - 1

Decimal Notation

x = - 0.18350 \dots, x = - 1.81649 \dots

Solution steps

\frac{1}{3 ( x + 1 )} = \frac{x + 1}{2}

Cross multiply

2 = 3 (x + 1)^{2}

Solve

2 = 3 (x + 1)^{2} : x = \frac{2}{3} - 1, x = - \frac{2}{3} - 1

x = \frac{2}{3} - 1, x = - \frac{2}{3} - 1

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = \frac{2}{3} - 1, x = - \frac{2}{3} - 1

\frac{6}{2 x} = 1

L, a = \frac{r}{2 L}

10 (\frac{910}{( 910 + x )}) = 5.6

\frac{8}{3} = \frac{9}{x}

2 = \frac{3}{7} - \frac{6}{b}

What is the answer to 1/(3(x+1))=(x+1)/2 ?
The answer to 1/(3(x+1))=(x+1)/2 is x=sqrt(2/3)-1,x=-sqrt(2/3)-1
Solve for x: 1/(3(x+1))=(x+1)/2
The solution is x=sqrt(2/3)-1,x=-sqrt(2/3)-1