What is the answer to y^2+8/y-9=0 ?

The answer to y^2+8/y-9=0 is y=1,y=(-1+sqrt(33))/2 ,y=(-1-sqrt(33))/2

Solve for y: y^2+8/y-9=0

The solution is y=1,y=(-1+sqrt(33))/2 ,y=(-1-sqrt(33))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} + \frac{8}{y} - 9 = 0

y = 1, y = \frac{- 1 + 33}{2}, y = \frac{- 1 - 33}{2}

Decimal Notation

y = 1, y = 2.37228 \dots, y = - 3.37228 \dots

Solution steps

y^{2} + \frac{8}{y} - 9 = 0

Multiply both sides by

y

y^{3} + 8 - 9 y = 0

Solve

y^{3} + 8 - 9 y = 0 : y = 1, y = \frac{- 1 + 33}{2}, y = \frac{- 1 - 33}{2}

y = 1, y = \frac{- 1 + 33}{2}, y = \frac{- 1 - 33}{2}

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y = 1, y = \frac{- 1 + 33}{2}, y = \frac{- 1 - 33}{2}

\frac{2}{x} = 11

2 = \frac{x + 2}{x - 12}

\frac{2}{x} = 2 x

2 = \frac{x + 2}{x - 11}

\frac{24}{s} = - 4

What is the answer to y^2+8/y-9=0 ?
The answer to y^2+8/y-9=0 is y=1,y=(-1+sqrt(33))/2 ,y=(-1-sqrt(33))/2
Solve for y: y^2+8/y-9=0
The solution is y=1,y=(-1+sqrt(33))/2 ,y=(-1-sqrt(33))/2