What is the answer to 2(1+x)^{-4}=1 ?

The answer to 2(1+x)^{-4}=1 is x=\sqrt[4]{2}-1,x=-\sqrt[4]{2}-1

Solve for x: 2(1+x)^{-4}=1

The solution is x=\sqrt[4]{2}-1,x=-\sqrt[4]{2}-1

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2 (1 + x)^{- 4} = 1

Decimal Notation

x = 0.18920 \dots, x = - 2.18920 \dots

Solution steps

2 (1 + x)^{- 4} = 1

Refine

\frac{2}{( 1 + x ) ^{4}} = 1

Multiply both sides by

(1 + x)^{4}

2 = (1 + x)^{4}

Solve

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

\frac{1}{2 x} = \frac{1}{4}

9 = \frac{18}{x}

\frac{1}{2 x} = \frac{1}{2}

x, \frac{4}{x} = d + 2 r

\frac{4260}{x} = 8.96

What is the answer to 2(1+x)^{-4}=1 ?
The answer to 2(1+x)^{-4}=1 is x=\sqrt[4]{2}-1,x=-\sqrt[4]{2}-1
Solve for x: 2(1+x)^{-4}=1
The solution is x=\sqrt[4]{2}-1,x=-\sqrt[4]{2}-1