What is the answer to 0=(x^2-1)/(x^3-2x^2) ?

The answer to 0=(x^2-1)/(x^3-2x^2) is x=1,x=-1

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0=(x^2-1)/(x^3-2x^2)

0 = \frac{x ^{2} - 1}{x ^{3} - 2 x ^{2}}

x = 1, x = - 1

Solution steps

0 = \frac{x ^{2} - 1}{x ^{3} - 2 x ^{2}}

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

0 = x^{2} - 1

Solve

0 = x^{2} - 1 : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 0, x = 2

Combine undefined points with solutions:

x = 1, x = - 1

0.24 = \frac{21}{x}

\frac{( x ) ( x )}{( 0.5 - x )} = 8.3

\frac{3}{4 x - 2} = \frac{5}{7 x + 3}

\frac{3 x + 5}{5 x - 3} = - \frac{3}{5}

2 = \frac{1}{1 + c \cdot e ^{- 1}}

What is the answer to 0=(x^2-1)/(x^3-2x^2) ?
The answer to 0=(x^2-1)/(x^3-2x^2) is x=1,x=-1
Solve for x: 0=(x^2-1)/(x^3-2x^2)
The solution is x=1,x=-1