What is the answer to 3x+1=(-1)/(3x+2) ?

The answer to 3x+1=(-1)/(3x+2) is x=-1/2+i(sqrt(3))/6 ,x=-1/2-i(sqrt(3))/6

Solve for x: 3x+1=(-1)/(3x+2)

The solution is x=-1/2+i(sqrt(3))/6 ,x=-1/2-i(sqrt(3))/6

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3 x + 1 = \frac{- 1}{3 x + 2}

x = - \frac{1}{2} + i \frac{3}{6}, x = - \frac{1}{2} - i \frac{3}{6}

Solution steps

3 x + 1 = \frac{- 1}{3 x + 2}

Simplify

\frac{- 1}{3 x + 2} : - \frac{1}{3 x + 2}

3 x + 1 = - \frac{1}{3 x + 2}

Multiply both sides by

3 x + 2

3 x (3 x + 2) + 3 x + 2 = - 1

Solve

3 x (3 x + 2) + 3 x + 2 = - 1 : x = - \frac{1}{2} + i \frac{3}{6}, x = - \frac{1}{2} - i \frac{3}{6}

x = - \frac{1}{2} + i \frac{3}{6}, x = - \frac{1}{2} - i \frac{3}{6}

\frac{2 t}{k - 3} = \frac{8}{k - 2 t}

- \frac{1}{x - 1} = \frac{1}{1 - x}

\frac{2}{3 ( 12 x - 18 )} = 4

\frac{b - 10}{b - 9} = \frac{9}{7}

0 = 2 + \frac{1}{x + 4}

What is the answer to 3x+1=(-1)/(3x+2) ?
The answer to 3x+1=(-1)/(3x+2) is x=-1/2+i(sqrt(3))/6 ,x=-1/2-i(sqrt(3))/6
Solve for x: 3x+1=(-1)/(3x+2)
The solution is x=-1/2+i(sqrt(3))/6 ,x=-1/2-i(sqrt(3))/6