What is the answer to a^2=(-k^2)/(1-k) ?

The answer to a^2=(-k^2)/(1-k) is k=-(-a^2+asqrt(a^2-4))/2 ,k=-(-a^2-asqrt(a^2-4))/2

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a^2=(-k^2)/(1-k)

a^{2} = \frac{- k ^{2}}{1 - k}

k = - \frac{- a ^{2} + a a ^{2} - 4}{2}, k = - \frac{- a ^{2} - a a ^{2} - 4}{2}

Solution steps

a^{2} = \frac{- k ^{2}}{1 - k}

Simplify

\frac{- k ^{2}}{1 - k} : - \frac{k ^{2}}{1 - k}

a^{2} = - \frac{k ^{2}}{1 - k}

Multiply both sides by

1 - k

a^{2} (1 - k) = - k^{2}

Solve

a^{2} (1 - k) = - k^{2} : k = - \frac{- a ^{2} + a a ^{2} - 4}{2}, k = - \frac{- a ^{2} - a a ^{2} - 4}{2}

k = - \frac{- a ^{2} + a a ^{2} - 4}{2}, k = - \frac{- a ^{2} - a a ^{2} - 4}{2}

\frac{x + 1}{2 - x} = \frac{x}{x - 3}

2 x + 1 = \frac{15}{x}

\frac{11}{x + 1} = \frac{3}{x - 1}

10 = \frac{100}{10 x - 120}

\frac{32}{24} = \frac{60}{x}

What is the answer to a^2=(-k^2)/(1-k) ?
The answer to a^2=(-k^2)/(1-k) is k=-(-a^2+asqrt(a^2-4))/2 ,k=-(-a^2-asqrt(a^2-4))/2