What is the answer to solvefor x,x^{-1}=y-1 ?

The answer to solvefor x,x^{-1}=y-1 is x= 1/(y-1);\quad y\ne 1

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solvefor x,x^{-1}=y-1

solve for

x, x^{- 1} = y - 1

x = \frac{1}{y - 1}; y \neq = 1

Solution steps

x^{- 1} = y - 1

Refine

\frac{1}{x} = y - 1

Multiply both sides by

x

1 = y x - x

Switch sides

y x - x = 1

Factor

y x - x : x (y - 1)

x (y - 1) = 1

Divide both sides by

y - 1; y \neq = 1

x = \frac{1}{y - 1}; y \neq = 1

\frac{x - 5}{x + 8} = \frac{2}{7}

v, C = \frac{Q}{v}

\frac{x ^{4}}{x} = \frac{48}{24}

t, \frac{d}{t} = r

\frac{5}{3 x + 8} + \frac{2}{x - 1} = 0

What is the answer to solvefor x,x^{-1}=y-1 ?
The answer to solvefor x,x^{-1}=y-1 is x= 1/(y-1);\quad y\ne 1