What is the answer to (6x-3)/(x^2-9x+2)=0 ?

The answer to (6x-3)/(x^2-9x+2)=0 is x= 1/2

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(6x-3)/(x^2-9x+2)=0

\frac{6 x - 3}{x ^{2} - 9 x + 2} = 0

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

\frac{6 x - 3}{x ^{2} - 9 x + 2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

6 x - 3 = 0

Move

3

to the right side

6 x = 3

Divide both sides by

6

x = \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = \frac{9 + 73}{2}, x = \frac{9 - 73}{2}

Combine undefined points with solutions:

x = \frac{1}{2}

- \frac{1}{p} - 1 = - p

0.999 = \frac{R}{R + 1.6}

\frac{3 π}{4} = \frac{2 π}{b}

- 2 = - \frac{2}{x ^{2}}

\frac{2.4}{m} = \frac{3}{4.5}

What is the answer to (6x-3)/(x^2-9x+2)=0 ?
The answer to (6x-3)/(x^2-9x+2)=0 is x= 1/2
Solve for x: (6x-3)/(x^2-9x+2)=0
The solution is x= 1/2