What is the answer to 6t^{-2}-5t^{-1}+1=0 ?

The answer to 6t^{-2}-5t^{-1}+1=0 is t=3,t=2

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6t^{-2}-5t^{-1}+1=0

6 t^{- 2} - 5 t^{- 1} + 1 = 0

t = 3, t = 2

Solution steps

6 t^{- 2} - 5 t^{- 1} + 1 = 0

Refine

\frac{6}{t ^{2}} - \frac{5}{t} + 1 = 0

Multiply by LCM

6 - 5 t + t^{2} = 0

Solve

6 - 5 t + t^{2} = 0 : t = 3, t = 2

t = 3, t = 2

Verify Solutions

Find undefined (singularity) points:

t = 0

Combine undefined points with solutions:

t = 3, t = 2

m, p = \frac{r t}{m v}

g (2) = \frac{n - 1}{n}

\frac{4 ( n + 1 ) !}{( n - 1 ) !} = 168

\frac{2}{x} + \frac{5}{3 x} = 1

\frac{3 x}{x + 1} = 7 - \frac{3}{x + 1}

What is the answer to 6t^{-2}-5t^{-1}+1=0 ?
The answer to 6t^{-2}-5t^{-1}+1=0 is t=3,t=2
Solve for t: 6t^{-2}-5t^{-1}+1=0
The solution is t=3,t=2