What are the solutions to the equation 4a^2-20a+25=0 ?

The solutions to the equation 4a^2-20a+25=0 are a= 5/2

Find the zeros of 4a^2-20a+25=0

The zeros of 4a^2-20a+25=0 are a= 5/2

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4 a^{2} - 20 a + 25 = 0

a = \frac{5}{2}

Solution steps

4 a^{2} - 20 a + 25 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

a_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

a = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

a = \frac{5}{2}

The solution to the quadratic equation is:

a = \frac{5}{2}

6 x^{2} + 37 x + 6

- 5 ∣ 2 + 4 x ∣ = - 32 (x + \frac{3}{4}) - ∣ x ∣ + 1

\frac{5 ^{- 3}}{5 ^{6}}

8 x^{3} y + 2 x^{4} - 8 x^{4} y

x^{2} y - x y^{2}

What are the solutions to the equation 4a^2-20a+25=0 ?
The solutions to the equation 4a^2-20a+25=0 are a= 5/2
Find the zeros of 4a^2-20a+25=0
The zeros of 4a^2-20a+25=0 are a= 5/2