What is the answer to (20t)/(t^2+4)=4 ?

The answer to (20t)/(t^2+4)=4 is t=4,t=1

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(20t)/(t^2+4)=4

\frac{20 t}{t ^{2} + 4} = 4

t = 4, t = 1

Solution steps

\frac{20 t}{t ^{2} + 4} = 4

Multiply both sides by

t^{2} + 4

20 t = 4 (t^{2} + 4)

Solve

20 t = 4 (t^{2} + 4) : t = 4, t = 1

t = 4, t = 1

\frac{1}{x - 2} + 2 = \frac{11}{x - 2}

\frac{5}{x} + \frac{3}{4} = 7

(z + 1) (z + 2) = 1 + 3 z^{- 1} + 2 z^{- 2}

x, x^{- 3} + y^{3} = 27

\frac{2 ( - x ^{2} + 18 )}{x ^{3}} = - 5

What is the answer to (20t)/(t^2+4)=4 ?
The answer to (20t)/(t^2+4)=4 is t=4,t=1
Solve for t: (20t)/(t^2+4)=4
The solution is t=4,t=1