What is the answer to 2/(x-1)=1+1/(x-2) ?

The answer to 2/(x-1)=1+1/(x-2) is x=2+i,x=2-i

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2/(x-1)=1+1/(x-2)

\frac{2}{x - 1} = 1 + \frac{1}{x - 2}

x = 2 + i, x = 2 - i

Solution steps

\frac{2}{x - 1} = 1 + \frac{1}{x - 2}

Multiply by LCM

2 (x - 2) = (x - 1) (x - 2) + x - 1

Solve

2 (x - 2) = (x - 1) (x - 2) + x - 1 : x = 2 + i, x = 2 - i

x = 2 + i, x = 2 - i

- 0.02 x + 140 = \frac{1}{50 x + 10}

\frac{x}{x + 1} = 3

\frac{1}{2 x} = 5 \cdot 1 0^{- 4}

\frac{( x + 12 )}{x} = \frac{3}{2}

\frac{1}{2 x + 3 y - 2} = 0

What is the answer to 2/(x-1)=1+1/(x-2) ?
The answer to 2/(x-1)=1+1/(x-2) is x=2+i,x=2-i
Solve for x: 2/(x-1)=1+1/(x-2)
The solution is x=2+i,x=2-i