What is the answer to (2x-1}{x+1}=\frac{1-x)/x ?

The answer to (2x-1}{x+1}=\frac{1-x)/x is x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6

Solve for x: (2x-1}{x+1}=\frac{1-x)/x

The solution is x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6

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\frac{2 x - 1}{x + 1} = \frac{1 - x}{x}

x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

Decimal Notation

x = 0.76759 \dots, x = - 0.43425 \dots

Solution steps

\frac{2 x - 1}{x + 1} = \frac{1 - x}{x}

Cross multiply

(2 x - 1) x = (x + 1) (1 - x)

Solve

(2 x - 1) x = (x + 1) (1 - x) : x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 0

Combine undefined points with solutions:

x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

X + \frac{1}{X} = 3

x, y + 1 = \frac{1}{x} - 1

x, z = \frac{1}{x y}

- 18 x + 36 = \frac{16 x - 12}{x + 18}

\frac{4}{h} = \frac{8}{10}

What is the answer to (2x-1}{x+1}=\frac{1-x)/x ?
The answer to (2x-1}{x+1}=\frac{1-x)/x is x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6
Solve for x: (2x-1}{x+1}=\frac{1-x)/x
The solution is x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6