What is the answer to solvefor f,f^{-1}(x)=e^{2x-1} ?

The answer to solvefor f,f^{-1}(x)=e^{2x-1} is f= x/(e^{2x-1)}

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solvefor f,f^{-1}(x)=e^{2x-1}

solve for

f, f^{- 1} (x) = e^{2 x - 1}

f = \frac{x}{e ^{2 x - 1}}

Solution steps

f^{- 1} (x) = e^{2 x - 1}

Refine

\frac{x}{f} = e^{2 x - 1}

Multiply both sides by

f

x = e^{2 x - 1} f

Switch sides

e^{2 x - 1} f = x

Divide both sides by

e^{2 x - 1}

f = \frac{x}{e ^{2 x - 1}}

y, - \frac{1}{y - 1} = x

\frac{5}{x} = \frac{20}{x} + 3

1.1 = 2 - \frac{1}{x}

\frac{5}{3} = \frac{10}{x}

x, y = \frac{4}{x}

What is the answer to solvefor f,f^{-1}(x)=e^{2x-1} ?
The answer to solvefor f,f^{-1}(x)=e^{2x-1} is f= x/(e^{2x-1)}