What is the answer to x=(3x)/(x^2+1) ?

The answer to x=(3x)/(x^2+1) is x=0,x=-sqrt(2),x=sqrt(2)

Solve for x: x=(3x)/(x^2+1)

The solution is x=0,x=-sqrt(2),x=sqrt(2)

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x = \frac{3 x}{x ^{2} + 1}

x = 0, x = - 2, x = 2

Decimal Notation

x = 0, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

x = \frac{3 x}{x ^{2} + 1}

Multiply both sides by

x^{2} + 1

x (x^{2} + 1) = 3 x

Solve

x (x^{2} + 1) = 3 x : x = 0, x = - 2, x = 2

x = 0, x = - 2, x = 2

22.75 = \frac{1000}{x}

h, b = \frac{m}{h ^{2}}

\frac{6 x ^{2} - 16}{3 x} = 12 + 2 x

\frac{6}{x} = \frac{42}{63}

\frac{3}{x \cdot y - y ^{2}} = 0

What is the answer to x=(3x)/(x^2+1) ?
The answer to x=(3x)/(x^2+1) is x=0,x=-sqrt(2),x=sqrt(2)
Solve for x: x=(3x)/(x^2+1)
The solution is x=0,x=-sqrt(2),x=sqrt(2)