What is the answer to 1/81 =b^{-4} ?

The answer to 1/81 =b^{-4} is b=3,b=-3,b=3i,b=-3i

Solve for b: 1/81 =b^{-4}

The solution is b=3,b=-3,b=3i,b=-3i

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\frac{1}{81} = b^{- 4}

b = 3, b = - 3, b = 3 i, b = - 3 i

Solution steps

\frac{1}{81} = b^{- 4}

Refine

\frac{1}{81} = \frac{1}{b ^{4}}

Cross multiply

b^{4} = 81

Solve

b^{4} = 81 : b = 3, b = - 3, b = 3 i, b = - 3 i

b = 3, b = - 3, b = 3 i, b = - 3 i

Verify Solutions

Find undefined (singularity) points:

b = 0

Combine undefined points with solutions:

b = 3, b = - 3, b = 3 i, b = - 3 i

\frac{1}{x} - 3 x = \frac{( 2 - x )}{3}

\frac{45}{x} = 15

\frac{1}{1 + a} = 1 + \frac{1}{a}

0.7 = \frac{200}{x}

20 = \frac{100 A}{- 1 + A}

What is the answer to 1/81 =b^{-4} ?
The answer to 1/81 =b^{-4} is b=3,b=-3,b=3i,b=-3i
Solve for b: 1/81 =b^{-4}
The solution is b=3,b=-3,b=3i,b=-3i