What are the solutions to the equation -x^2+12x-20=0 ?

The solutions to the equation -x^2+12x-20=0 are x=2,x=10

Find the zeros of -x^2+12x-20=0

The zeros of -x^2+12x-20=0 are x=2,x=10

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- x^{2} + 12 x - 20 = 0

x = 2, x = 10

Solution steps

- x^{2} + 12 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 1 ) ( - 20 )}{2 ( - 1 )}

1 2^{2} - 4 (- 1) (- 20) = 8

x_{1, 2} = \frac{- 12 \pm 8}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 12 + 8}{2 ( - 1 )}, x_{2} = \frac{- 12 - 8}{2 ( - 1 )}

x = \frac{- 12 + 8}{2 ( - 1 )} : 2

x = \frac{- 12 - 8}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = 2, x = 10

18 x^{2} - 54 x + 36 = 0

(25 x)^{\frac{1}{2}}

3 x + 9 = x + 1

\frac{x}{5} + (1 - x) = - 27

4 x^{2} - 20 x = - 13

What are the solutions to the equation -x^2+12x-20=0 ?
The solutions to the equation -x^2+12x-20=0 are x=2,x=10
Find the zeros of -x^2+12x-20=0
The zeros of -x^2+12x-20=0 are x=2,x=10