What is the answer to (-2x-2)/(x^2+2x)=0 ?

The answer to (-2x-2)/(x^2+2x)=0 is x=-1

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(-2x-2)/(x^2+2x)=0

\frac{- 2 x - 2}{x ^{2} + 2 x} = 0

x = - 1

Solution steps

\frac{- 2 x - 2}{x ^{2} + 2 x} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x - 2 = 0

Move

2

to the right side

- 2 x = 2

Divide both sides by

- 2

x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 0, x = - 2

Combine undefined points with solutions:

x = - 1

\frac{n !}{( n - 2 ) !} = 56

\frac{1}{x} = \frac{1}{x - 5}

\frac{x}{x - 6} = \frac{x - 2}{- x + 6}

0.001 = (\frac{1}{1 + 0.5 x})^{2}

\frac{4}{5} = \frac{6}{b} - 1

What is the answer to (-2x-2)/(x^2+2x)=0 ?
The answer to (-2x-2)/(x^2+2x)=0 is x=-1
Solve for x: (-2x-2)/(x^2+2x)=0
The solution is x=-1