What is the answer to solvefor j,a=(j+b)/(j-c) ?

The answer to solvefor j,a=(j+b)/(j-c) is j=(b+ac)/(a-1);\quad a\ne 1

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solvefor j,a=(j+b)/(j-c)

solve for

j, a = \frac{j + b}{j - c}

j = \frac{b + a c}{a - 1}; a \neq = 1

Solution steps

a = \frac{j + b}{j - c}

Multiply both sides by

j - c

a (j - c) = j + b

Expand

a (j - c) : ja - a c

ja - a c = j + b

Move

a c

to the right side

ja = j + b + a c

Move

j

to the left side

ja - j = b + a c

Factor

ja - j : j (a - 1)

j (a - 1) = b + a c

Divide both sides by

a - 1; a \neq = 1

j = \frac{b + a c}{a - 1}; a \neq = 1

y, y = \frac{6}{y}

13 + \frac{6}{y} y = 6

\frac{x}{\frac{2}{5} ( x - 2 )} = 4 x

x + \frac{1}{x} = 10

1 = \frac{10}{x}

What is the answer to solvefor j,a=(j+b)/(j-c) ?
The answer to solvefor j,a=(j+b)/(j-c) is j=(b+ac)/(a-1);\quad a\ne 1