What is the answer to ((-4x-4)/(x^2+2x+5))=0 ?

The answer to ((-4x-4)/(x^2+2x+5))=0 is x=-1

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((-4x-4)/(x^2+2x+5))=0

(\frac{- 4 x - 4}{x ^{2} + 2 x + 5}) = 0

x = - 1

Solution steps

(\frac{- 4 x - 4}{x ^{2} + 2 x + 5}) = 0

Simplify

(\frac{- 4 x - 4}{x ^{2} + 2 x + 5}) : \frac{- 4 x - 4}{x ^{2} + 2 x + 5}

\frac{- 4 x - 4}{x ^{2} + 2 x + 5} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 4 x - 4 = 0

Move

4

to the right side

- 4 x = 4

Divide both sides by

- 4

x = - 1

\frac{2}{x} - \frac{14}{x + 24} = 1

\frac{1}{2} = \frac{3 - 2 x}{4 x - 6}

\frac{5}{x + 3} + \frac{4}{x} = 3

x \frac{8}{a x} - 5 = - 3

2 = \frac{x + 11}{x - 12}

What is the answer to ((-4x-4)/(x^2+2x+5))=0 ?
The answer to ((-4x-4)/(x^2+2x+5))=0 is x=-1
Solve for x: ((-4x-4)/(x^2+2x+5))=0
The solution is x=-1