What is the answer to 400y^{-4}-41y^{-2}+1=0 ?

The answer to 400y^{-4}-41y^{-2}+1=0 is y=5,y=-5,y=4,y=-4

Solve for y: 400y^{-4}-41y^{-2}+1=0

The solution is y=5,y=-5,y=4,y=-4

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400 y^{- 4} - 41 y^{- 2} + 1 = 0

y = 5, y = - 5, y = 4, y = - 4

Solution steps

400 y^{- 4} - 41 y^{- 2} + 1 = 0

Refine

\frac{400}{y ^{4}} - \frac{41}{y ^{2}} + 1 = 0

Multiply by LCM

400 - 41 y^{2} + y^{4} = 0

Solve

400 - 41 y^{2} + y^{4} = 0 : y = 5, y = - 5, y = 4, y = - 4

y = 5, y = - 5, y = 4, y = - 4

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y = 5, y = - 5, y = 4, y = - 4

\frac{6}{9} = \frac{8}{x}

\frac{x}{x - 2} + 6 = \frac{2}{x - 2}

g, p = \frac{d}{r - g}

x, m = \frac{y}{x}

x, x y = \frac{2 x - 5}{x + 3}

What is the answer to 400y^{-4}-41y^{-2}+1=0 ?
The answer to 400y^{-4}-41y^{-2}+1=0 is y=5,y=-5,y=4,y=-4
Solve for y: 400y^{-4}-41y^{-2}+1=0
The solution is y=5,y=-5,y=4,y=-4