What is the answer to a(2-(-1/a))^2=1 ?

The answer to a(2-(-1/a))^2=1 is a=-3/8+i(sqrt(7))/8 ,a=-3/8-i(sqrt(7))/8

Solve for a: a(2-(-1/a))^2=1

The solution is a=-3/8+i(sqrt(7))/8 ,a=-3/8-i(sqrt(7))/8

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a (2 - (- \frac{1}{a}))^{2} = 1

a = - \frac{3}{8} + i \frac{7}{8}, a = - \frac{3}{8} - i \frac{7}{8}

Solution steps

a (2 - (- \frac{1}{a}))^{2} = 1

Simplify

a (2 - (- \frac{1}{a}))^{2} : 4 a + 4 + \frac{1}{a}

4 a + 4 + \frac{1}{a} = 1

Multiply both sides by

a

4 a^{2} + 4 a + 1 = a

Solve

4 a^{2} + 4 a + 1 = a : a = - \frac{3}{8} + i \frac{7}{8}, a = - \frac{3}{8} - i \frac{7}{8}

a = - \frac{3}{8} + i \frac{7}{8}, a = - \frac{3}{8} - i \frac{7}{8}

a, u = \frac{k}{2 a}

\frac{8}{x} + \frac{3}{x - 1} = 3

(20) = (\frac{70 x}{70 + x})

\frac{5}{2 x} = \frac{5}{6 x ^{2}}

\frac{9}{16} + \frac{1}{b ^{2}} = 1

What is the answer to a(2-(-1/a))^2=1 ?
The answer to a(2-(-1/a))^2=1 is a=-3/8+i(sqrt(7))/8 ,a=-3/8-i(sqrt(7))/8
Solve for a: a(2-(-1/a))^2=1
The solution is a=-3/8+i(sqrt(7))/8 ,a=-3/8-i(sqrt(7))/8