What is the answer to 2+1/(x+2)=(x+4)^2 ?

The answer to 2+1/(x+2)=(x+4)^2 is x=-3,x=(-7+sqrt(13))/2 ,x=(-7-sqrt(13))/2

Solve for x: 2+1/(x+2)=(x+4)^2

The solution is x=-3,x=(-7+sqrt(13))/2 ,x=(-7-sqrt(13))/2

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2 + \frac{1}{x + 2} = (x + 4)^{2}

x = - 3, x = \frac{- 7 + 13}{2}, x = \frac{- 7 - 13}{2}

Decimal Notation

x = - 3, x = - 1.69722 \dots, x = - 5.30277 \dots

Solution steps

2 + \frac{1}{x + 2} = (x + 4)^{2}

Multiply both sides by

x + 2

2 (x + 2) + 1 = (x + 4)^{2} (x + 2)

Solve

2 (x + 2) + 1 = (x + 4)^{2} (x + 2) : x = - 3, x = \frac{- 7 + 13}{2}, x = \frac{- 7 - 13}{2}

x = - 3, x = \frac{- 7 + 13}{2}, x = \frac{- 7 - 13}{2}

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = - 3, x = \frac{- 7 + 13}{2}, x = \frac{- 7 - 13}{2}

2 a = \frac{108}{r}

a = \frac{( 1 )}{( 2 ) h ( b + c )}

c, 945 = \frac{m c}{c + 1}

2 (\frac{1}{a} + 2) = 5 - \frac{2}{a}

\frac{1}{1 + x} = \frac{38}{31}

What is the answer to 2+1/(x+2)=(x+4)^2 ?
The answer to 2+1/(x+2)=(x+4)^2 is x=-3,x=(-7+sqrt(13))/2 ,x=(-7-sqrt(13))/2
Solve for x: 2+1/(x+2)=(x+4)^2
The solution is x=-3,x=(-7+sqrt(13))/2 ,x=(-7-sqrt(13))/2