What is the answer to 4x^{-2}+2x^{-1}-2=0 ?

The answer to 4x^{-2}+2x^{-1}-2=0 is x=-1,x=2

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4x^{-2}+2x^{-1}-2=0

4 x^{- 2} + 2 x^{- 1} - 2 = 0

x = - 1, x = 2

Solution steps

4 x^{- 2} + 2 x^{- 1} - 2 = 0

Refine

\frac{4}{x ^{2}} + \frac{2}{x} - 2 = 0

Multiply by LCM

4 + 2 x - 2 x^{2} = 0

Solve

4 + 2 x - 2 x^{2} = 0 : x = - 1, x = 2

x = - 1, x = 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 1, x = 2

\frac{1}{x + 1} = 1 - \frac{4}{x + 7}

\frac{3 x + 18}{x} = x

0.1 = \frac{1}{1 + k}

52 = - \frac{8}{x}

\frac{- 22 + 3 x}{3 x + 7} = 2

What is the answer to 4x^{-2}+2x^{-1}-2=0 ?
The answer to 4x^{-2}+2x^{-1}-2=0 is x=-1,x=2
Solve for x: 4x^{-2}+2x^{-1}-2=0
The solution is x=-1,x=2