What are the solutions to the equation -4.9t^2+3=0 ?

The solutions to the equation -4.9t^2+3=0 are t=(sqrt(30))/7 ,t=-(sqrt(30))/7

Find the zeros of -4.9t^2+3=0

The zeros of -4.9t^2+3=0 are t=(sqrt(30))/7 ,t=-(sqrt(30))/7

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- 4.9 t^{2} + 3 = 0

t = \frac{30}{7}, t = - \frac{30}{7}

Decimal Notation

t = 0.78246 \dots, t = - 0.78246 \dots

Solution steps

- 4.9 t^{2} + 3 = 0

Move

3

to the right side

- 4.9 t^{2} = - 3

Multiply both sides by

10

- 49 t^{2} = - 30

Divide both sides by

- 49

t^{2} = \frac{30}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{30}{49}, t = - \frac{30}{49}

\frac{30}{49} = \frac{30}{7}

- \frac{30}{49} = - \frac{30}{7}

t = \frac{30}{7}, t = - \frac{30}{7}

\frac{6}{5} + \frac{3}{4}

6 e^{\frac{πi}{6}}

lo g_{x^{2}} (x^{2} + 2 x + 1) \leq 1

(5 x + 3)^{2} = (3 x + 5)^{2}

4 (z + 2) = 3 (z + 1)

What are the solutions to the equation -4.9t^2+3=0 ?
The solutions to the equation -4.9t^2+3=0 are t=(sqrt(30))/7 ,t=-(sqrt(30))/7
Find the zeros of -4.9t^2+3=0
The zeros of -4.9t^2+3=0 are t=(sqrt(30))/7 ,t=-(sqrt(30))/7