What is the answer to (2k)/(k-1)=(21-k)/(2k) ?

The answer to (2k)/(k-1)=(21-k)/(2k) is k= 7/5 ,k=3

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(2k)/(k-1)=(21-k)/(2k)

\frac{2 k}{k - 1} = \frac{21 - k}{2 k}

k = \frac{7}{5}, k = 3

Decimal Notation

k = 1.4, k = 3

Solution steps

\frac{2 k}{k - 1} = \frac{21 - k}{2 k}

Cross multiply

4 k^{2} = (k - 1) (21 - k)

Solve

4 k^{2} = (k - 1) (21 - k) : k = \frac{7}{5}, k = 3

k = \frac{7}{5}, k = 3

Verify Solutions

Find undefined (singularity) points:

k = 1, k = 0

Combine undefined points with solutions:

k = \frac{7}{5}, k = 3

49 = \frac{( 3 x + 8 ) ^{2}}{x ^{2}}

w, x = \frac{5 y + 3 w}{2 w}

\frac{1}{x} = 4.25

\frac{( x + 3 )}{5} = \frac{2}{x}

\frac{120}{h} = 10

What is the answer to (2k)/(k-1)=(21-k)/(2k) ?
The answer to (2k)/(k-1)=(21-k)/(2k) is k= 7/5 ,k=3
Solve for k: (2k)/(k-1)=(21-k)/(2k)
The solution is k= 7/5 ,k=3