What is the answer to (x^2+x+2)/(x-1)=0 ?

The answer to (x^2+x+2)/(x-1)=0 is x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

Solve for x: (x^2+x+2)/(x-1)=0

The solution is x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{x ^{2} + x + 2}{x - 1} = 0

x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

Solution steps

\frac{x ^{2} + x + 2}{x - 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + x + 2 = 0

Solve

x^{2} + x + 2 = 0 : x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

0.66 = \frac{9}{x - 3}

\frac{21}{4 + y} = \frac{53}{4}

\frac{x - 5}{x + 6} = 0

\frac{2}{3 h} - \frac{1}{2 h} = - 1

\frac{x}{1 - x} = 2.5

What is the answer to (x^2+x+2)/(x-1)=0 ?
The answer to (x^2+x+2)/(x-1)=0 is x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2
Solve for x: (x^2+x+2)/(x-1)=0
The solution is x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2