What is the answer to solvefor x,y-1= 2/(x-3) ?

The answer to solvefor x,y-1= 2/(x-3) is x=(3y-1)/(y-1);\quad y\ne 1

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solvefor x,y-1= 2/(x-3)

solve for

x, y - 1 = \frac{2}{x - 3}

x = \frac{3 y - 1}{y - 1}; y \neq = 1

Solution steps

y - 1 = \frac{2}{x - 3}

Multiply both sides by

x - 3

y (x - 3) - (x - 3) = 2

Expand

y (x - 3) - (x - 3) : x y - 3 y - x + 3

x y - 3 y - x + 3 = 2

Move

3 y

to the right side

x y - x + 3 = 2 + 3 y

Move

3

to the right side

x y - x = 3 y - 1

Factor

x y - x : x (y - 1)

x (y - 1) = 3 y - 1

Divide both sides by

y - 1; y \neq = 1

x = \frac{3 y - 1}{y - 1}; y \neq = 1

\frac{- 288 x ^{2}}{( x - 12 ) ^{4}} = 0

\frac{9}{10} = \frac{22.5}{x}

1.126 = x + (\frac{0.175}{x ^{2}})

3 x - 5 = \frac{4}{x}

k, z = \frac{k + 3}{k + 6}

What is the answer to solvefor x,y-1= 2/(x-3) ?
The answer to solvefor x,y-1= 2/(x-3) is x=(3y-1)/(y-1);\quad y\ne 1