What is the answer to (25-x^2)/(x^2+5x)=0 ?

The answer to (25-x^2)/(x^2+5x)=0 is x=5

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(25-x^2)/(x^2+5x)=0

\frac{25 - x ^{2}}{x ^{2} + 5 x} = 0

x = 5

Solution steps

\frac{25 - x ^{2}}{x ^{2} + 5 x} = 0

Simplify

\frac{25 - x ^{2}}{x ^{2} + 5 x} : - \frac{x - 5}{x}

- \frac{x - 5}{x} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x - 5 = 0

Move

5

to the right side

x = 5

Verify Solutions

Find undefined (singularity) points:

x = 0, x = - 5

Combine undefined points with solutions:

x = 5

\frac{25 - x ^{2}}{x ^{2} + 5 x} = 1

\frac{13}{3} = \frac{26}{c}

\frac{x ^{2}}{1 + x ^{2}} = 0.83

yy = \frac{( 4 ) ( 3 )}{( y ) ( 8 )}

2 t + \frac{16}{t ^{2}} = 0

What is the answer to (25-x^2)/(x^2+5x)=0 ?
The answer to (25-x^2)/(x^2+5x)=0 is x=5
Solve for x: (25-x^2)/(x^2+5x)=0
The solution is x=5